How many pounds of active ingredient (A.I.) are required for a 500-gallon tank to achieve a concentration of 100 ppm, given a formulation contains 5.4 pounds A.I. per gallon?

To determine the amount of active ingredient (A.I.) required for a 500-gallon tank to achieve a concentration of 100 parts per million (ppm), it's essential to understand the relationship between concentration, volume, and the active ingredient's specifics.

First, let's convert the desired concentration from ppm to pounds. A concentration of 100 ppm means that for every million parts (or units) of water, there are 100 parts of active ingredient.

In a 500-gallon tank:

1. Understand that there are approximately 8.34 pounds of water in a gallon. Therefore, a 500-gallon volume contains about 4,170 pounds of water (500 gallons x 8.34 pounds/gallon).

2. To find out how many pounds correspond to 100 ppm, you can calculate:

( 4,170 \text{ pounds of water} \times \frac{100}{1,000,000} = 0.417 \text{ pounds of A.I.} ).

When considering the formulation containing 5.4 pounds of A.I. per gallon, this information may help in further calculations or applications but is not directly needed to find the total A.I. required for the specified